Binding Machines Buying Guide

Question by Solong N: Independent event an probability?
A person is playing a slot machine. He makes the comment “I have been playing this damn thing for over three hours and haven’t won yet! I will keep playing because I am bound to hit soon!” What’s wrong with what he said? Explain your answer using independent events and probability.

Best answer:

Answer by sandynlily
each individual spin of the reels is an event with outcomes of fixed odds, every time he experiences a losing event, the losing event is not removed from the pool of events of which the random events occur from and the odds of winning and losing remain the same pull after pull regardless of how many times he spins and loses. Assuming that the odds of the slot mahcine are set against him, it would not be in his better interest to continue playing the machine, as the odds of him winning have not changes at all and he is still expecting to lose.

Lesson be learned, this happens all of the time in casinos, do not chase your losses.

Know better? Leave your own answer in the comments!

Question by Juan C: probability question… need help…?
A printing company’s bookbinding machine has a probability of 0.005 of producing a defective book. If this machine is used to bind three books…

how do you find the probability that…

a.) none of the books are defective
b.) at least one of the book is defective
c.) all of the books are defective

Best answer:

Answer by fcas80
a. .995*.995*.995

b. 1 – .995*.995*.995

c. .005*.005*.005

Add your own answer in the comments!

Question by snookiebear69: A printing companies book binding machine has a probability of .005 of producing a defective book.?
This machine is used to bind three books.
A. Find the probability that none of the books is defective.
B. Find the probability that at least one is defective.
C. Find the probability that all of the books are defective

Best answer:

Answer by Julius N
p = .005, q = .995

X / P(X) probability distribution:

0 / .985
1 / .01485
2 / .00007462
3 / .000000125

A. 0.985
B. 1.000 – .985 = .015
C. 0.000000125

Give your answer to this question below!

Question by snookiebear69: A printing companies book binding machine has a probability of .005 of producing a defective book.?
This machine is used to bind three books.
A. Find the probability that none of the books is defective.
B. Find the probability that at least one is defective.
C. Find the probability that all of the books are defective

Best answer:

Answer by Julius N
p = .005, q = .995

X / P(X) probability distribution:

0 / .985
1 / .01485
2 / .00007462
3 / .000000125

A. 0.985
B. 1.000 – .985 = .015
C. 0.000000125

Know better? Leave your own answer in the comments!

Question by snookiebear69: A printing companies book binding machine has a probability of .005 of producing a defective book.?
This machine is used to bind three books.
A. Find the probability that none of the books is defective.
B. Find the probability that at least one is defective.
C. Find the probability that all of the books are defective

Best answer:

Answer by Julius N
p = .005, q = .995

X / P(X) probability distribution:

0 / .985
1 / .01485
2 / .00007462
3 / .000000125

A. 0.985
B. 1.000 – .985 = .015
C. 0.000000125

What do you think? Answer below!