A printing companies book binding machine has a probability of .005 of producing a defective book.?
Tuesday, March 30th, 2010 at
12:34 pm
This machine is used to bind three books.
A. Find the probability that none of the books is defective.
B. Find the probability that at least one is defective.
C. Find the probability that all of the books are defective
Tagged with: .005 • Binding • book • companies • defective • Machine • printing • probability • producing
Filed under: binding machine review
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p = .005, q = .995
X / P(X) probability distribution:
0 / .985
1 / .01485
2 / .00007462
3 / .000000125
A. 0.985
B. 1.000 – .985 = .015
C. 0.000000125
Use P = p^r * q^(n-r) * nCr
Where P = probability of r sucesses,
p = probability of success in a single trial
q = 1 – p = probability of failure in a single trial
n = number of trials
A) P = .995^3 * .005^0 * 3C3 = .98507
B) This is the same as 1 minus the probability that none are defective.
P = 1 – (.995^3 * .005^0 * 3C3) = .01493
C) P = .995^0 * .005^3 * 3C0 = .000000125